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fix: --file flag description for uc deploy cmd

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This commit is contained in:
Pavel Sviderski
2025-04-30 11:45:25 +10:00
parent c56385602e
commit db3016fe89
2 changed files with 2 additions and 2 deletions
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cmd/uncloud/deploy.go
+1 -1
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@@ -40,7 +40,7 @@ func NewDeployCommand() *cobra.Command {
} }
cmd.Flags().StringSliceVarP(&opts.files, "file", "f", nil, cmd.Flags().StringSliceVarP(&opts.files, "file", "f", nil,
"One or more Compose files to deploy services from. (default compose-ports-long.yaml)") "One or more Compose files to deploy services from. (default compose.yaml)")
cmd.Flags().StringVarP(&opts.context, "context", "c", "", cmd.Flags().StringVarP(&opts.context, "context", "c", "",
"Name of the cluster context to deploy to (default is the current context)") "Name of the cluster context to deploy to (default is the current context)")
// TODO: Consider adding a filter flag to specify which machines to deploy to but keep the rest running. // TODO: Consider adding a filter flag to specify which machines to deploy to but keep the rest running.
pkg/client/compose/project.go
+1 -1
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@@ -23,7 +23,7 @@ func LoadProject(ctx context.Context, paths []string) (*types.Project, error) {
composecli.WithDotEnv, composecli.WithDotEnv,
// Get compose file path set by COMPOSE_FILE. // Get compose file path set by COMPOSE_FILE.
composecli.WithConfigFileEnv, composecli.WithConfigFileEnv,
// If none was selected, get default compose-ports-long.yaml file from current dir or parent folders. // If none was selected, get default Compose file names from current or parent folders.
composecli.WithDefaultConfigPath, composecli.WithDefaultConfigPath,
composecli.WithExtension(PortsExtensionKey, PortsSource{}), composecli.WithExtension(PortsExtensionKey, PortsSource{}),
) )